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Detector and Instrument Validation

A detector or instrument model is credible only when separate tests challenge its response, normalization, complete positivity, spacetime support, energy balance, perturbative approximation, numerical convergence, and data lineage. Agreement with the same calculation used to design the model is calibration, not independent validation. This page turns those principles into a fully reproducible inertial-detector benchmark and shows how seeded faults test whether the checks have power.

Required background. Localized detector models defines the physical probe, and local measurement instruments defines the probability and update maps that must be tested.

Helpful background. Switching, smearing, and regularization supplies the regulator and limit-order checks.

Chapter map. Use the route from a local coupling to a field instrument, the chapter claim-validity table, and the three independent validity questions to place this construction within the full measurement protocol.

Record the field theory and state, detector Hilbert space, trajectory or worldtube, switching χ\chi, smearing FF, coupling, initial probe state, readout POVM, perturbative order, discretization, and analytic or software version. If a parameter is changed after viewing a result, the result belongs to calibration; reserve an untouched observable, parameter point, or implementation for validation.

The main checks answer different questions:

CheckQuestionRepresentative failure
NullDoes a forbidden or switched-off response vanish?Background offset
Positivity and normalizationIs this a valid probability law or instrument?Negative branch probability
Analytic benchmarkDo conventions and numerical integrals agree with an independent formula?Fourier-factor or gap error
Causal supportDoes the nonselective operation act trivially on the causal complement?Switching or smearing tail
ConvergenceAre cutoffs and quadratures resolved independently?Shared unresolved grid
Energy balanceDoes control work equal field plus probe energy change?Missing switching work
Perturbative scalingIs the omitted order smaller than the claim tolerance?Hidden O(λ4)O(\lambda^4) term
Cross-modelDoes a second realization expose implementation dependence?Same POVM, different update

Passing one row does not license another. In particular, a nonnegative response does not prove causal support, and a small quadrature residual does not bound a perturbative remainder.

Consider a two-level Unruh–DeWitt detector at rest in the four-dimensional massless-scalar vacuum. Set the monopole matrix element to one and use

χ(t)=e−t2/(2T2),F(x)=e−x2/(2L2)(2πL2)3/2.\chi(t)=e^{-t^2/(2T^2)}, \qquad F(\mathbf x)=\frac{e^{-\mathbf x^2/(2L^2)}}{(2\pi L^2)^{3/2}}.

Fix Fourier conventions by

χ~(ν)=∫dt e−iνtχ(t)=2π Te−T2ν2/2,\widetilde\chi(\nu)=\int dt\,e^{-i\nu t}\chi(t) =\sqrt{2\pi}\,T e^{-T^2\nu^2/2}, F~(k)=∫d3x e−ik⋅xF(x)=e−L2k2/2.\widetilde F(\mathbf k)=\int d^3x\,e^{-i\mathbf k\cdot\mathbf x}F(\mathbf x) =e^{-L^2\mathbf k^2/2}.

The leading excitation probability is Pg→e=λ2F(Ω)+O(λ4)P_{g\to e}=\lambda^2\mathcal F(\Omega)+O(\lambda^4). The general double-integral response is given in Satz 2007, Eqs. (2.2)–(2.5). In the present inertial smeared model, the mode expansion gives the independent spectral representation

F(Ω)=∫d3k2(2π)3∣k∣∣F~(k)∣2∣χ~(Ω+∣k∣)∣2.\mathcal F(\Omega) =\int\frac{d^3k}{2(2\pi)^3|\mathbf k|} \left|\widetilde F(\mathbf k)\right|^2 \left|\widetilde\chi(\Omega+|\mathbf k|)\right|^2.

Angular integration reduces this to one positive integral,

F(Ω)=T22π∫0∞dk kexp⁡ ⁣[−L2k2−T2(k+Ω)2].\mathcal F(\Omega) =\frac{T^2}{2\pi}\int_0^\infty dk\,k \exp\!\left[-L^2k^2-T^2(k+\Omega)^2\right].

Define

a=L2+T2,b=T2Ω,c=T2Ω2.a=L^2+T^2, \qquad b=T^2\Omega, \qquad c=T^2\Omega^2.

Completing the square gives the analytic value

F(Ω)=T2e−c2π[12a−bπ2aaeb2/aerfc⁡ ⁣(ba)].\mathcal F(\Omega) =\frac{T^2e^{-c}}{2\pi} \left[ \frac{1}{2a} -\frac{b\sqrt\pi}{2a\sqrt a} e^{b^2/a}\operatorname{erfc}\!\left(\frac{b}{\sqrt a}\right) \right].

Take TT as the time unit, so numerical energies are reported in T−1T^{-1}, and choose

LT=1,ΩT=1,λ=0.1,\frac{L}{T}=1, \qquad \Omega T=1, \qquad \lambda=0.1,

the exact leading response and probability are

F(1/T)=0.005039976195438958,\mathcal F(1/T)=0.005039976195438958, Pg→e(2)=λ2F(1)=0.0000503997619543896.P_{g\to e}^{(2)} =\lambda^2\mathcal F(1) =0.0000503997619543896.

The switched-off null is exactly Pg→e(2)(λ=0)=0P_{g\to e}^{(2)}(\lambda=0)=0. A numerical implementation should reproduce the response without using the closed form. Composite Simpson integration on 0≤kT≤80\le kT\le8 gives:

Subintervals NNNumerical F(1/T)\mathcal F(1/T)Absolute error from the analytic value
320.0050378486394377360.0050378486394377362.13×10−62.13\times10^{-6}
640.0050399506965394590.0050399506965394592.55×10−82.55\times10^{-8}
1280.0050399758192406640.0050399758192406643.76×10−103.76\times10^{-10}
2560.0050399761896420970.0050399761896420975.80×10−125.80\times10^{-12}

The integrand is positive, the radial measure contributes the factor kk, and the 2π2\pi coefficient is fixed by the declared Fourier transform. These simple invariants catch many convention errors. Spatial-profile regularization and the pointlike limit are analyzed in Louko and Satz 2006, §§ 2–4; smooth switching and the sharp-switching limit are separated in Satz 2007, §§ 3–4.

A validation suite should fail on deliberately corrupted inputs.

Gap bias. Replace the declared Ω=1\Omega=1 by Ω=1.05\Omega=1.05 in the integrand while leaving the report unchanged. The analytic formula gives

F(1.05)=0.004349377658520056,\mathcal F(1.05)=0.004349377658520056,

a relative shift of −13.7024%-13.7024\%. The analytic comparison catches this error even if the biased numerical quadrature is internally converged.

Perturbative-order error. Feed the analysis synthetic data

Pseed(λ)=λ2F(1)(1+0.8λ2)P_{\mathrm{seed}}(\lambda) =\lambda^2\mathcal F(1)(1+0.8\lambda^2)

while fitting a pure quadratic. The diagnostic ratio is

Pseed(λ)λ2F(1)=1+0.8λ2,\frac{P_{\mathrm{seed}}(\lambda)}{\lambda^2\mathcal F(1)} =1+0.8\lambda^2,

which equals 1.0081.008, 1.0321.032, and 1.0721.072 at λ=0.1,0.2,0.3\lambda=0.1,0.2,0.3. A multi-coupling test therefore exposes the missing order even when a single small-λ\lambda run looks accurate.

Support leak. Both Gaussian profiles in the benchmark have nonzero tails and therefore cannot validate an exact spacelike-support claim. For the causal test, replace them by a temporal bump χc∈C0∞(R)\chi_c\in C_0^\infty(\mathbb R) and a normalized spatial bump Fc∈C0∞(R3)F_c\in C_0^\infty(\mathbb R^3), and verify that the complete worldtube K=supp⁡χc×supp⁡FcK=\operatorname{supp}\chi_c\times\operatorname{supp}F_c is spacelike separated from the receiver. Then seed the temporal leak

χseed(t)=χc(t)+10−3χc(t−tleak),\chi_{\mathrm{seed}}(t) =\chi_c(t)+10^{-3}\chi_c(t-t_{\mathrm{leak}}),

while retaining the compact spatial profile, with the translated temporal bump making the full leaked worldtube enter the receiver’s causal past. The geometry checker must now reject exact spacelike separation; geometry alone does not prove that one chosen marginal changes. To test the dynamics as well, choose a receiver observable and state for which the leaked coupling has a proved nonzero response, then require the implementation to detect that response. A complementary seed can translate FcF_c so that its support enters the receiver’s causal past while leaving χc\chi_c fixed. Without a demonstrated dynamical response, downgrade the result only to “exact no signaling not certified,” not to a claim that signaling was observed. Causal factorization for supported probe couplings is the independent structural check; see Fewster and Verch 2020, Theorem 3.5 and Eqs. (3.28)–(3.30).

If any seeded fault passes, the corresponding unseeded claim is not validated. This is especially important when two apparently independent calculations reuse the same code, regulator, or Fourier convention.

A useful acceptance quantity for non-null runs is

Rn=∣Pn+1−Pn∣max⁡(Pn+1,Pscale),R_n =\frac{|P_{n+1}-P_n|} {\max(P_{n+1},P_{\mathrm{scale}})},

where PscaleP_{\mathrm{scale}} prevents meaningless relative errors near zero. Report time and momentum domains, grid sequences, tail estimates, perturbative fits, input units, source versions and hashes, random seeds where applicable, raw and transformed outputs, failed and passed null tests, and the rule used to accept or downgrade the claim. Preserve negative and seeded-failure results.

Scientific evidence boundary, checked 2026-08-26. The cited literature and the benchmark above validate the stated leading-order, smeared inertial model and the local system–probe composition framework. They do not validate a sharp detector, a nonperturbative response, exact support for Gaussian profiles, or every detector trajectory and field state. Each extension needs its own regulator, convergence, causal, and approximation evidence.

Using two quadratures with the same unresolved cutoff. Agreement is not independent if both methods share the same bias. Compare a closed form or a genuinely different representation.

Interpreting the Gaussian benchmark as compact support. Gaussian profiles are analytically convenient and never vanish exactly. Use a compact profile for exact causal separation or state a tail bound.

Combining numerical and perturbative error. Grid refinement controls integration, not omitted O(λ4)O(\lambda^4) physics. Estimate the two remainders separately.

Starting from the three-dimensional spectral integral, derive the one-dimensional coefficient T2/(2π)T^2/(2\pi).

Solution

Write d3k=4πk2dkd^3k=4\pi k^2dk. The field normalization contributes [2(2π)3k]−1[2(2\pi)^3k]^{-1}, so the angular integral gives k/(4π2)k/(4\pi^2). Since ∣χ~∣2=2πT2e−T2(k+Ω)2|\widetilde\chi|^2=2\pi T^2e^{-T^2(k+\Omega)^2}, multiplication leaves T2k/(2π)T^2k/(2\pi). The spatial factor is ∣F~∣2=e−L2k2|\widetilde F|^2=e^{-L^2k^2}.

Evaluate the radial integral analytically by completing the square.

Solution

With a,b,ca,b,c as defined,

I=e−c∫0∞dk ke−ak2−2bk.I=e^{-c}\int_0^\infty dk\,k e^{-ak^2-2bk}.

Let

J(b)=∫0∞dk e−ak2−2bk=π2aeb2/aerfc⁡ ⁣(ba).J(b)=\int_0^\infty dk\,e^{-ak^2-2bk} =\frac{\sqrt\pi}{2\sqrt a}e^{b^2/a} \operatorname{erfc}\!\left(\frac b{\sqrt a}\right).

Because I=−e−cJ′(b)/2I=-e^{-c}J'(b)/2 and J′(b)=2bJ/a−1/aJ'(b)=2bJ/a-1/a, one obtains

I=e−c[12a−bπ2aaeb2/aerfc⁡ ⁣(ba)].I=e^{-c}\left[ \frac1{2a}-\frac{b\sqrt\pi}{2a\sqrt a} e^{b^2/a}\operatorname{erfc}\!\left(\frac b{\sqrt a}\right) \right].

Multiplication by T2/(2π)T^2/(2\pi) gives the displayed response.

Why can the synthetic fourth-order seed evade a single run at λ=0.1\lambda=0.1 but not the three-point scaling test?

Solution

At λ=0.1\lambda=0.1, the correction multiplies the quadratic result by only 1.0081.008, so an 0.8%0.8\% discrepancy could be absorbed into calibration or a loose error bar. Dividing by λ2\lambda^2 at three couplings exposes a systematic increase: the normalized ratios are 1.0081.008, 1.0321.032, and 1.0721.072. A true leading-order coefficient would be constant up to the declared remainder, so the curvature diagnoses the seeded λ4\lambda^4 term.

  • Fewster, C. J., and Verch, R. (2020). “Quantum Fields and Local Measurements.” Communications in Mathematical Physics 378, 851–889. DOI. Open PDF.
  • Louko, J., and Satz, A. (2006). “How Often Does the Unruh–DeWitt Detector Click? Regularisation by a Spatial Profile.” Classical and Quantum Gravity 23, 6321–6344. DOI. Open PDF.
  • Satz, A. (2007). “Then Again, How Often Does the Unruh–DeWitt Detector Click If We Switch It Carefully?” Classical and Quantum Gravity 24, 1719–1732. DOI. Open PDF.

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