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Complete Passivity, KMS Structure, and Resource Conversion

A passive state may hide work that becomes accessible when several copies are operated on jointly. Complete passivity excludes this activation at every finite copy number. Under the standard CC^*-dynamical hypotheses, it singles out ground states and KMS equilibrium states rather than arbitrary decreasing energy populations.

Required background. Passivity, work, and information defines the Hamiltonian reference, admissible cyclic operations, and finite-energy domain used here.

Helpful background. KMS correlators connect the analytic KMS condition with modular flow.

If (A,αt,ω)(\mathcal A,\alpha_t,\omega) is a dynamical system, the nn-copy system has state ωn\omega^{\otimes n} and product dynamics αtn\alpha_t^{\otimes n}. Complete passivity means that every ωn\omega^{\otimes n} is passive against every admissible cyclic perturbation of the composite:

Wext(n)(U,ωn)0,n=1,2,.W_{\rm ext}^{(n)}(U,\omega^{\otimes n})\le0, \qquad n=1,2,\ldots .

The collective unitary need not factor across copies. That point is essential: restricting to U1UnU_1\otimes\cdots\otimes U_n would merely repeat the one-copy test and could not reveal activation.

Pusz and Woronowicz 1978, Theorems 1.1 and 1.4, pp. 275–281 show, subject to their dynamical assumptions, that completely passive states are KMS states at a common inverse temperature β0\beta\ge0 or ground states. KMS analyticity is therefore not inferred from a single successful work-extraction test; it follows from stability against all finite-copy cyclic processes.

Consider one three-level system with energies (0,ϵ,2ϵ)(0,\epsilon,2\epsilon) and probabilities p0p1p2p_0\ge p_1\ge p_2. The state is passive. It is thermal only if

p1p0=p2p1=eβϵ\frac{p_1}{p_0}=\frac{p_2}{p_1}=e^{-\beta\epsilon}

for one β\beta. If these ratios differ, tensor products contain pairs of composite levels whose population order conflicts with total energy order. At some finite copy number a collective permutation lowers the energy. The resulting work is a resource-conversion witness for athermality, not a violation of one-copy passivity.

For a regulated field, use a finite set of modes and an energy cutoff, locate an inverted pair in ρn\rho^{\otimes n}, and then increase the cutoff. A conclusion about the continuum requires a uniform finite-energy construction; an activation that recedes to infinite energy does not define an admissible QFT protocol.

Separate hypothesis chains lead from cyclic dynamics to passivity, sampled stress energy to QEI or ANEC, modular data to an entropy–energy bound, null shape variation to QNEC, and localized instruments to cost or QET.

Complete passivity strengthens the first branch by allowing collective cyclic operations on every finite tensor power. Its KMS conclusion does not derive the separate stress-energy or entropy bounds. The diagram is schematic.

Several qualifications prevent overstatement:

  • Copies must share a specified dynamics and temperature scale. Combining unrelated Hamiltonian normalizations can manufacture a spurious gradient.
  • A catalyst must return in its full state, including correlations if the resource theory requires them. Returning only its marginal can leave hidden resources in correlations.
  • An unbounded-energy catalyst can invalidate finite-energy work accounting. State an energy constraint and approximation topology.
  • Conserved charges replace HH by a generalized potential such as HμQH-\mu Q only when the charge sector and admissible operations are fixed.

A proposed bound passes through independent checks of operator domain, averaging geometry, renormalization and species, and full operational energy accounting; omissions lead to four distinct false conclusions.

The multi-copy theorem is vulnerable to changed composition rules, uncontrolled sectors, and catalysts without a finite-energy return condition. These are domain failures, not exceptions to the theorem. The map is schematic.

Show that a Gibbs state ρβ=eβH/Z\rho_\beta=e^{-\beta H}/Z remains Gibbs for the sum Hamiltonian on nn noninteracting copies.

Solution

Because the copy Hamiltonians commute, eβiHi=ieβHie^{-\beta\sum_i H_i}=\bigotimes_i e^{-\beta H_i} and the partition function is ZnZ^n. Hence ρβn\rho_\beta^{\otimes n} is Gibbs at the same β\beta and is passive for every nn.

  • Pusz, Władysław, and Stanisław L. Woronowicz. “Passive States and KMS States for General Quantum Systems.” Communications in Mathematical Physics 58 (1978): 273–290. DOI.