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Loops and regularization

A loop integral is not defined merely by writing an integral sign. Its ultraviolet, infrared, and threshold regions have different physical origins; a regulator makes intermediate expressions meaningful but can also disturb symmetries or hide the domain in which an expansion is valid. This lesson develops one logarithmically divergent integral in two regulators and shows which parts of the answer can be compared before any renormalization condition is imposed.

Required background. Perturbative expansion and Feynman rules supplies propagators, vertices, loop measures, and symmetry factors. LSZ reduction and tree amplitudes supplies the distinction between a loop correction to a correlator and a correction to a physical amplitude. Helpful background. Review complex and asymptotic methods if contour deformation or analytic continuation is the blocking step.

Classify the singular region before choosing a regulator

Section titled “Classify the singular region before choosing a regulator”

For large Euclidean momentum kk, a scalar propagator behaves as k−2k^{-2}. A one-loop integrand with two propagators in four dimensions therefore has

∫Λd4k k−4∼∫Λdkk,\int^{\Lambda}\mathrm d^4k\,k^{-4} \sim\int^{\Lambda}\frac{\mathrm dk}{k},

so it is logarithmically ultraviolet divergent. This estimate says where the problem lies and how it scales; it does not define the integral or determine its finite part.

Other singular regions require different responses:

RegionDiagnostic questionTypical control
UltravioletDoes the integrand fail to decay at large loop momentum?Cutoff, dimensional regularization, lattice spacing, Pauli–Villars fields, or another declared UV regulator
InfraredDo massless or on-shell denominators become singular at small momentum or long distance?Mass, finite volume, off-shellness, dimensional continuation, or an inclusive observable
Threshold or pinchDo poles trap the contour as external invariants cross a physical threshold?The inherited i0i0, analytic continuation, and a stated sheet
SpuriousDid an algebraic split create terms more singular than their sum?Recombine terms before assigning physical meaning

A UV counterterm cannot remove a physical threshold cut, and an infrared-safe observable is not produced by subtracting a UV pole. Keep the classifications separate even when one regulator happens to display more than one of them.

One Euclidean integral exposes the ultraviolet logarithm

Section titled “One Euclidean integral exposes the ultraviolet logarithm”

Take m>0m>0 and define

I(m)=∫d4kE(2π)41(kE2+m2)2.I(m)=\int\frac{\mathrm d^4k_E}{(2\pi)^4} \frac{1}{(k_E^2+m^2)^2}.

The mass removes the small-kEk_E singularity, so any divergence here is ultraviolet. A sharp rotationally invariant cutoff gives

IΛ(m)=∫∣kE∣<Λd4kE(2π)41(kE2+m2)2.I_\Lambda(m) =\int_{|k_E|<\Lambda}\frac{\mathrm d^4k_E}{(2\pi)^4} \frac{1}{(k_E^2+m^2)^2}.

Using the area 2π22\pi^2 of the unit three-sphere,

IΛ(m)=18π2∫0Λk3 dk(k2+m2)2=116π2[log⁡Λ2+m2m2+m2Λ2+m2−1].\begin{aligned} I_\Lambda(m) &=\frac{1}{8\pi^2}\int_0^\Lambda \frac{k^3\,\mathrm dk}{(k^2+m^2)^2}\\ &=\frac{1}{16\pi^2} \left[ \log\frac{\Lambda^2+m^2}{m^2} +\frac{m^2}{\Lambda^2+m^2}-1 \right]. \end{aligned}

Thus

IΛ(m)=116π2[log⁡Λ2m2−1+O ⁣(m2Λ2)].I_\Lambda(m) =\frac{1}{16\pi^2} \left[ \log\frac{\Lambda^2}{m^2}-1 +\mathcal O\!\left(\frac{m^2}{\Lambda^2}\right) \right].

The coefficient of the logarithm is robust in comparisons that preserve the same low-energy normalization. The constant −1-1 belongs to this particular cutoff shape and definition. Changing the regulator can change such local finite terms before renormalized parameters are matched.

Dimensional regularization displays the same coefficient

Section titled “Dimensional regularization displays the same coefficient”

Continue the Euclidean dimension to d=4−2ϵd=4-2\epsilon and introduce a reference scale μ\mu so that the integral keeps its four-dimensional mass dimension:

Id(m;μ)=μ2ϵ∫ddkE(2π)d1(kE2+m2)2.I_d(m;\mu) =\mu^{2\epsilon} \int\frac{\mathrm d^d k_E}{(2\pi)^d} \frac{1}{(k_E^2+m^2)^2}.

The Schwinger representation and Gaussian integral give

1(kE2+m2)2=∫0∞ds s e−s(kE2+m2),\frac{1}{(k_E^2+m^2)^2} =\int_0^\infty\mathrm ds\,s\,e^{-s(k_E^2+m^2)},

and

∫ddkE(2π)de−skE2=(4πs)−d/2.\int\frac{\mathrm d^d k_E}{(2\pi)^d}e^{-sk_E^2} =(4\pi s)^{-d/2}.

Therefore

Id(m;μ)=μ2ϵ(4π)d/2Γ ⁣(2−d2)(m2)d/2−2.I_d(m;\mu) =\frac{\mu^{2\epsilon}}{(4\pi)^{d/2}} \Gamma\!\left(2-\frac d2\right) (m^2)^{d/2-2}.

Expanding at small positive ϵ\epsilon gives

Id(m;μ)=116π2[1ϵ−γE+log⁡4π+log⁡μ2m2+O(ϵ)].I_d(m;\mu) =\frac{1}{16\pi^2} \left[ \frac1\epsilon-\gamma_E+\log4\pi +\log\frac{\mu^2}{m^2} +\mathcal O(\epsilon) \right].

The 1/ϵ1/\epsilon pole represents the same logarithmic ultraviolet sensitivity as log⁡Λ2\log\Lambda^2. The scalar master integral and its expansion are developed in Schwartz 2014, App. B.3.2–3, pp. 826–828. His Lorentzian master integral carries a Wick-rotation factor ii, absent from our Euclidean integral. His convention d=4−ϵSd=4-\epsilon_{\mathrm S} gives 2/ϵS2/\epsilon_{\mathrm S}; setting ϵS=2ϵ\epsilon_{\mathrm S}=2\epsilon gives our 1/ϵ1/\epsilon. A regulator does not make the theory finite: a subtraction and renormalization condition are still required.

With the modified minimal-subtraction scale μ‾2=4πe−γEμ2\overline\mu^2=4\pi e^{-\gamma_E}\mu^2, the bracket becomes

1ϵ+log⁡μ‾2m2+O(ϵ).\frac1\epsilon+\log\frac{\overline\mu^2}{m^2} +\mathcal O(\epsilon).

That notation packages two constants; it is a scheme convention, not a new physical scale. In the canonical logarithmic master-integral expansion, track the pole, Euler constant and four-pi factor together before choosing a subtraction.

External momentum reveals thresholds as well as UV behavior

Section titled “External momentum reveals thresholds as well as UV behavior”

The equal-mass bubble before continuation has the schematic form

B(p2)=μ2ϵ∫ddk(2π)dik2−m2+i0i(k+p)2−m2+i0.B(p^2)=\mu^{2\epsilon} \int\frac{\mathrm d^d k}{(2\pi)^d} \frac{i}{k^2-m^2+i0} \frac{i}{(k+p)^2-m^2+i0}.

Feynman parameterization uses

1AB=∫01dx[xA+(1−x)B]2.\frac1{AB}=\int_0^1\frac{\mathrm dx}{[xA+(1-x)B]^2}.

After a regulated shift of loop momentum, the denominator depends on

Δ(x,p2)=m2−x(1−x)p2.\Delta(x,p^2)=m^2-x(1-x)p^2.

The UV pole is independent of p2p^2 because large loop momentum cannot resolve the external scale at leading order. The finite part contains log⁡[Δ(x,p2)−i0]\log[\Delta(x,p^2)-i0]. Since x(1−x)≤1/4x(1-x)\le1/4, the argument can vanish for p2≥4m2p^2\ge4m^2, producing the two-particle branch cut. That nonanalyticity is physical threshold information, not a UV divergence to subtract Srednicki 2006 draft, § 15, pp. 120–121, Eq. (15.5) and threshold discussion, PDF.

Compare the canonical massive Euclidean bubble: its momentum-independent UV pole and finite momentum dependence have the same roles. Its Euclidean normalization does not include the two Lorentzian propagator factors of ii displayed here.

The shift of loop momentum deserves emphasis. In an absolutely convergent integral it is an ordinary change of variables. Dimensional regularization can establish that identity in a convergence domain and then analytically continue the regulated result Srednicki 2006 draft, § 14, pp. 111–114, Eqs. (14.12–14.18), PDF. A change of variables moves a sharp cutoff ball as well. Imposing the original ball again after the shift changes the finite regulator. Symmetry cancellations that compare different loop routings must use one consistent prescription; this observation alone does not establish a nonzero Ward-violating surface term for the present logarithmic bubble. The loop-shift identities in dimensional continuation are discussed in ’t Hooft and Veltman 1972, § 3, p. 197.

Power counting predicts candidates, not final answers

Section titled “Power counting predicts candidates, not final answers”

For a scalar graph in four dimensions with propagators behaving as k−2k^{-2}, the superficial degree of divergence is

ω=4L−2I.\omega=4L-2I.

In quartic theory, 4V=2I+E4V=2I+E and, for a connected graph, L=I−V+1L=I-V+1. Eliminating II and VV gives

ω=4−E.\omega=4-E.

Two-point graphs are superficially quadratic, four-point graphs logarithmic, and graphs with more external legs superficially convergent. This is only a first screen. Symmetry can cancel the leading terms; derivative numerators can worsen counting; and a graph with ω<0\omega<0 can contain divergent subgraphs. Renormalization must treat all divergent subgraphs consistently, not just the overall large-momentum limit Srednicki 2006 draft, § 18, pp. 129–131, Eqs. (18.2–18.8) and subdivergences, PDF.

Regulators are judged by what they preserve and expose

Section titled “Regulators are judged by what they preserve and expose”

Before accepting a regulated result, state:

  • the integration contour or Euclidean continuation;
  • the regulator and parameters being held fixed;
  • which symmetries are exact, broken, or recovered only after counterterms;
  • the order in which regulator, volume, mass, and on-shell limits are taken;
  • every UV, IR, and threshold singular region; and
  • one independent check, such as a Ward identity, derivative with respect to a mass, or agreement of a universal logarithm across regulators.

No regulator is selected solely by making an integral easy. A lattice gives a nonperturbative UV definition but breaks continuous rotations at finite spacing. A sharp momentum cutoff requires care with loop-momentum translations and symmetry identities. Pauli–Villars fields can preserve some symmetries but add heavy auxiliary content.

The scale-covariant analytic prescription of dimensional regularization assigns zero to scaleless integrals. That zero does not establish the absence of UV or IR singular regions: analytically continued endpoint pieces can contain cancelling UV and IR poles Schwartz 2014, App. B.3.3, p. 829, Eqs. (B.48–B.49). Use the canonical scaleless UV/IR separation to separate those endpoints before extracting ultraviolet information.

Gauge identities must be checked with the chosen continuation and subtraction prescription. Intrinsically four-dimensional objects such as γ5\gamma^5 and Levi-Civita tensors require an explicit continuation prescription; their ordinary four-dimensional identities cannot simply all be imposed in general dimension ’t Hooft and Veltman 1972, § 6, pp. 206–208.

Evaluate IΛ(m)I_\Lambda(m) by setting u=k2u=k^2. Verify both its dimension and its large-Λ\Lambda limit.

Solution

The angular integral gives 1/(8π2)1/(8\pi^2), and k3dk=u du/2k^3\mathrm dk=u\,\mathrm du/2. Hence

IΛ=116π2∫0Λ2u du(u+m2)2.I_\Lambda =\frac{1}{16\pi^2} \int_0^{\Lambda^2}\frac{u\,\mathrm du}{(u+m^2)^2}.

An antiderivative is

log⁡(u+m2)+m2u+m2.\log(u+m^2)+\frac{m^2}{u+m^2}.

Evaluating the endpoints gives

IΛ=116π2[log⁡Λ2+m2m2+m2Λ2+m2−1].I_\Lambda =\frac{1}{16\pi^2} \left[ \log\frac{\Lambda^2+m^2}{m^2} +\frac{m^2}{\Lambda^2+m^2}-1 \right].

The measure has mass dimension four and the denominator dimension four, so the result is dimensionless. Expanding at large cutoff recovers [log⁡(Λ2/m2)−1]/(16π2)[\log(\Lambda^2/m^2)-1]/(16\pi^2) plus terms suppressed by m2/Λ2m^2/\Lambda^2.

2. Expand the dimensionally regulated integral

Section titled “2. Expand the dimensionally regulated integral”

Starting from the Gamma-function result, use Γ(ϵ)=1/ϵ−γE+O(ϵ)\Gamma(\epsilon)=1/\epsilon-\gamma_E+\mathcal O(\epsilon) to reproduce the pole and logarithm.

Solution

For d=4−2ϵd=4-2\epsilon,

Id=1(4π)2Γ(ϵ)(4πμ2m2)ϵ.I_d =\frac{1}{(4\pi)^2} \Gamma(\epsilon) \left(\frac{4\pi\mu^2}{m^2}\right)^\epsilon.

The second factor is

1+ϵlog⁡4πμ2m2+O(ϵ2).1+\epsilon\log\frac{4\pi\mu^2}{m^2} +\mathcal O(\epsilon^2).

Multiplying gives

Id=116π2[1ϵ−γE+log⁡4π+log⁡μ2m2+O(ϵ)].I_d =\frac{1}{16\pi^2} \left[ \frac1\epsilon-\gamma_E+\log4\pi +\log\frac{\mu^2}{m^2} +\mathcal O(\epsilon) \right].

The coefficient of 1/ϵ1/\epsilon matches the coefficient of log⁡Λ2\log\Lambda^2 in the cutoff result.

For a connected graph in four-dimensional ϕ4\phi^4 theory, use line-end and topology identities to show ω=4−E\omega=4-E. Explain why this does not prove that every six-point graph is finite.

Solution

Counting line ends gives 4V=2I+E4V=2I+E, and connected topology gives L=I−V+1L=I-V+1. Therefore

ω=4(I−V+1)−2I=2I−4V+4=4−E.\begin{aligned} \omega &=4(I-V+1)-2I\\ &=2I-4V+4\\ &=4-E. \end{aligned}

For E=6E=6, the overall degree is −2-2, so the graph is superficially convergent. It can still contain a two- or four-point subgraph with nonnegative degree. The corresponding subintegral must be renormalized before the full graph is assigned a finite value.

Continue from regulation to renormalization

Section titled “Continue from regulation to renormalization”

You are ready to continue when you can identify the singular region, derive the same logarithmic coefficient with a cutoff and dimensional continuation, state what each regulator preserves, and distinguish the UV pole from the two-particle threshold.

Next, Renormalization and the renormalization group introduces renormalized inputs, counterterms, scheme dependence, and scale evolution. Do not remove the pole by an unnamed subtraction: the finite definition of the parameters is part of the physical prediction.

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