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Maxwell Constraints as a Worked Application

Free Maxwell theory is the first field-theory example in which a singular Legendre map, constraint stabilization, and a gauge quotient can all be followed explicitly. The absent velocity A˙0\dot A_0 gives the primary constraint π00\pi^0\approx0; preserving it gives Gauss law as a secondary constraint; and the two first-class constraints organize one spacetime gauge function. After imposing the constraints and quotienting the admitted gauge directions, the physical initial data are one transverse canonical pair, with two configuration-space polarizations.

This page performs only that source-free Maxwell calculation on a fixed time slice in four-dimensional Minkowski space. It assumes regular fields and boundary data for which the displayed Hamiltonians and generators are differentiable. Boundary charges, harmonic and topological sectors, general constraint theory, gauge-generator algorithms, BRST/BV, and quantization are kept outside the calculation.

Required background. Hamiltonian Initial Data and Phase Space supplies canonical momenta, degenerate Legendre maps, equal-time Poisson brackets, and Hamiltonian evolution. The Free Maxwell Field and Gauge Redundancy supplies the action, field strength, equations, Gauss law, and Abelian gauge equivalence.

Helpful background. Constraints, Dirac Brackets, and Symplectic Reduction supplies the reusable first-/second-class and quotient framework.

The Maxwell Legendre map has one null velocity

Section titled “The Maxwell Legendre map has one null velocity”

Take the spatial slice to be Σ=R3\Sigma=\mathbb R^3. Fields and their variations fall off rapidly enough that the spatial surface terms displayed below vanish, and admitted gauge parameters are compactly supported or obey the corresponding vanishing condition. These assumptions also exclude harmonic and zero-mode sectors when the transverse decomposition is used later. Spatial contractions use δij\delta_{ij}.

Keep the lower components Aμ=(A0,Ai)A_\mu=(A_0,A_i) as the canonical coordinates throughout. With

F0i=A˙iiA0,LM=12F0iF0i14FijFij,\begin{aligned} F_{0i}&=\dot A_i-\partial_iA_0, \\ \mathcal L_{\mathrm M} &=\frac12F_{0i}F_{0i} -\frac14F_{ij}F_{ij}, \end{aligned}

the momenta are

πνLMA˙ν=F0ν,π0=0,πi=F0i=Ei.\begin{aligned} \pi^\nu &\equiv \frac{\partial\mathcal L_{\mathrm M}} {\partial\dot A_\nu} =-F^{0\nu}, \\ \pi^0&=0, \qquad \pi^i=F_{0i}=E_i. \end{aligned}

The velocity Hessian in the order (A0,Ai)(A_0,A_i) is therefore

Wμν=2LMA˙μA˙ν=(000δij).W^{\mu\nu} = \frac{\partial^2\mathcal L_{\mathrm M}} {\partial\dot A_\mu\partial\dot A_\nu} = \begin{pmatrix} 0&0\\ 0&\delta^{ij} \end{pmatrix}.

Its rank is three. The spatial velocities are recovered as

A˙i=πi+iA0,\dot A_i=\pi_i+\partial_iA_0,

but no equation recovers A˙0\dot A_0. The image of the Legendre map is instead restricted by the primary constraint

ϕ1(x)=π0(x)0.\phi_1(\mathbf x)=\pi^0(\mathbf x)\approx0.

Here \approx denotes equality after restriction to the final constraint surface; brackets must be evaluated before making that restriction. The electromagnetic momenta and primary relation are derived in Weinberg 1995, § 8.2, pp. 344–345. The general singular-Lagrangian step is worked in Brown 2022, § IV, p. 5.

The canonical Hamiltonian makes A₀ a multiplier

Section titled “The canonical Hamiltonian makes A₀ a multiplier”

Using only the three invertible velocities gives

Hc=12πiπi+14FijFij+πiiA0.\mathcal H_c =\frac12\pi^i\pi_i +\frac14F_{ij}F_{ij} +\pi^i\partial_iA_0.

The final term must not be integrated by parts silently. Before the boundary assumption is imposed,

Hc=Σd3x(12π2+14FijFijA0iπi)+ΣdSA0niπi.\begin{aligned} H_c ={}&\int_\Sigma\mathrm d^3x\, \left( \frac12\boldsymbol\pi^2 +\frac14F_{ij}F_{ij} -A_0\,\partial_i\pi^i \right) \\ &+\int_{\partial\Sigma}\mathrm dS\, A_0n_i\pi^i. \end{aligned}

Under the declared falloff the surface integral vanishes. Define

G(x)iπi(x),\mathcal G(\mathbf x) \equiv\partial_i\pi^i(\mathbf x),

and add an arbitrary multiplier u(t,x)u(t,\mathbf x) for the primary constraint:

HT=Σd3xHT,HT=12π2+14FijFijA0G+uπ0.\begin{aligned} H_T&=\int_\Sigma\mathrm d^3x\, \mathcal H_T, \\ \mathcal H_T &=\frac12\boldsymbol\pi^2 +\frac14F_{ij}F_{ij} -A_0\mathcal G +u\pi^0. \end{aligned}

Thus A0A_0 and uu play different roles. The field A0A_0 already occurs in the canonical Hamiltonian as the multiplier of Gauss law, whereas uu is the undetermined velocity A˙0\dot A_0 introduced with the primary constraint.

Stabilization produces Gauss law and then closes

Section titled “Stabilization produces Gauss law and then closes”

Use the equal-time bracket

{F,G}=Σd3xδFδAμδGδπμΣd3xδFδπμδGδAμ.\begin{aligned} \{F,G\} ={}&\int_\Sigma\mathrm d^3x\, \frac{\delta F}{\delta A_\mu} \frac{\delta G}{\delta\pi^\mu} \\ &-\int_\Sigma\mathrm d^3x\, \frac{\delta F}{\delta\pi^\mu} \frac{\delta G}{\delta A_\mu}. \end{aligned}

Equivalently, the fundamental bracket is

{Aμ(x),πν(y)}=δμνδ(3)(xy).\{A_\mu(\mathbf x),\pi^\nu(\mathbf y)\} =\delta_\mu{}^\nu \delta^{(3)}(\mathbf x-\mathbf y).

The primary constraint must hold at every time. Its Hamiltonian derivative is

π˙0(x)={π0(x),HT}=G(x)0.\dot\pi^0(\mathbf x) =\{\pi^0(\mathbf x),H_T\} =\mathcal G(\mathbf x) \approx0.

Hence

ϕ2(x)=G(x)=iπi(x)0\phi_2(\mathbf x) =\mathcal G(\mathbf x) =\partial_i\pi^i(\mathbf x) \approx0

is the secondary constraint. Because πi=Ei\pi^i=E_i, it is precisely source-free Gauss law. Its preservation gives

G˙=iπ˙i=ijFji=0,\dot{\mathcal G} =\partial_i\dot\pi^i =\partial_i\partial_jF_{ji} =0,

where the last equality follows from the antisymmetry of FjiF_{ji}. There is no tertiary constraint, and no consistency equation fixes uu.

For a distributionally safe classification, smear both constraints with admissible test functions. All three brackets vanish strongly:

{π0[f],π0[g]}=0,{π0[f],G[g]}=0,{G[f],G[g]}=0.\begin{aligned} \{\pi^0[f],\pi^0[g]\}&=0, \\ \{\pi^0[f],\mathcal G[g]\}&=0, \\ \{\mathcal G[f],\mathcal G[g]\}&=0. \end{aligned}

Both constraints are therefore first class. This conclusion uses the stabilized set and its bracket algebra, not merely the singular Hessian. Weinberg 1995, § 8.2, pp. 344–345 gives the Maxwell primary and Gauss constraints, their first-class character, and preservation of Gauss law. Brown 2022, §§ VI–X, pp. 6–11, PDF develops the general stabilization and classification steps used here in a finite-dimensional model.

Hamilton’s equations provide an independent sign check:

A˙0=u,π˙0=iπi,A˙i=πi+iA0,π˙i=jFji.\begin{aligned} \dot A_0&=u, &\dot\pi^0&=\partial_i\pi^i, \\ \dot A_i&=\pi_i+\partial_iA_0, &\dot\pi^i&=\partial_jF_{ji}. \end{aligned}

The first spatial equation recovers πi=F0i\pi^i=F_{0i}. The second is the source-free Ampère equation, and its divergence reproduces preservation of Gauss law.

Section titled “One gauge function links the two constraints”

The Gauss constraint alone generates the spatial part of a gauge transformation. With

Gsp[α]=Σd3xαG,G_{\mathrm{sp}}[\alpha] =-\int_\Sigma\mathrm d^3x\, \alpha\mathcal G,

integration by parts gives

δαAi={Ai,Gsp[α]}=iα,δαA0=0.\delta_\alpha A_i =\{A_i,G_{\mathrm{sp}}[\alpha]\} =\partial_i\alpha, \qquad \delta_\alpha A_0=0.

For time-dependent α\alpha, this slice transformation alone is not the full spacetime transformation: it omits the change of A0A_0. The primary constraint supplies the complementary instantaneous flow. If

P[β]=Σd3xβπ0,P[\beta] =\int_\Sigma\mathrm d^3x\, \beta\pi^0,

then

{A0,P[β]}=β,{Ai,P[β]}=0,{πμ,P[β]}=0.\begin{aligned} \{A_0,P[\beta]\}&=\beta, &\{A_i,P[\beta]\}&=0, \\ \{\pi^\mu,P[\beta]\}&=0. \end{aligned}

These are not two unrelated gauge symmetries. To match the Lagrangian redundancy δαAμ=μα\delta_\alpha A_\mu=\partial_\mu\alpha, their descriptors are tied by β=α˙\beta=\dot\alpha: the value of one function α(t,x)\alpha(t,\mathbf x) controls the longitudinal spatial shift, and its first time derivative controls A0A_0 on the same slice. The general construction of the tuned generator, including its action on multipliers, belongs to Gauge Orbits, Gauss Constraints, and Stabilizers.

Zinn-Justin 2021, § 21.5.2, p. 518 independently exhibits the Gauss constraint as the generator of the residual spatial transformation after temporal gauge has been chosen. That restricted statement supports GspG_{\mathrm{sp}} above; the relation to the four-component Lagrangian transformation is supplied by the linked instantaneous flows and β=α˙\beta=\dot\alpha, while the general tuned-generator construction is handed off.

The constraint surface also makes the gauge direction geometrically visible. Pull back the canonical two-form

ΩΣ=Σd3x(δA0δπ0+δAiδπi).\Omega_\Sigma =\int_\Sigma\mathrm d^3x\, \left( \boldsymbol\delta A_0\wedge\boldsymbol\delta\pi^0 +\boldsymbol\delta A_i\wedge\boldsymbol\delta\pi^i \right).

For a tangent variation, δπ0=0\boldsymbol\delta\pi^0=0 and iδπi=0\partial_i\boldsymbol\delta\pi^i=0. Contracting ΩΣ\Omega_\Sigma with the gauge vector gives a term proportional to

Σd3xiαδπi=Σd3xαiδπi=0,\int_\Sigma\mathrm d^3x\, \partial_i\alpha\, \boldsymbol\delta\pi^i =-\int_\Sigma\mathrm d^3x\, \alpha\,\partial_i\boldsymbol\delta\pi^i =0,

where the boundary term vanishes by assumption. The admitted gauge flow is therefore a null direction of the pulled-back two-form. General conditions for turning such null leaves into a smooth quotient remain with Mathematical Methods.

The complete chain is summarized below. Read it from the degenerate Legendre map through stabilization, then inspect how the primary flow controls A0A_0 and the Gauss flow controls the longitudinal part of AiA_i before the transverse quotient.

Maxwell's primary constraint stabilizes to Gauss law; their linked gauge directions leave a transverse canonical pair with two polarizations.

Schematic Maxwell constraint flow on R3\mathbb R^3 with the stated falloff and no harmonic or zero modes. The primary constraint π00\pi^0\approx0 stabilizes to G=iπi0\mathcal G=\partial_i\pi^i\approx0, and both are first class. The primary flow changes A0A_0 while the Gauss flow changes the longitudinal part of AiA_i; matching the covariant redundancy ties their descriptors by β=α˙\beta=\dot\alpha. Imposing the constraints and quotienting this admitted gauge direction leaves (AiT,πTi)(A_i^T,\pi_T^i): four phase-space dimensions, or two configuration-space polarizations, per nonzero momentum mode. The diagram is not to scale.

Under the stated assumptions, decompose the spatial canonical variables as

Ai=AiT+iχ,iAiT=0,πi=πTi+iσ,iπTi=0.\begin{aligned} A_i&=A_i^T+\partial_i\chi, &\partial_iA_i^T&=0, \\ \pi^i&=\pi_T^i+\partial^i\sigma, &\partial_i\pi_T^i&=0. \end{aligned}

Gauss law becomes 2σ=0\nabla^2\sigma=0. With the harmonic and zero modes excluded, σ=0\sigma=0, so the momentum is transverse. The gauge transformation shifts χχ+α\chi\mapsto\chi+\alpha and leaves AiTA_i^T unchanged. The primary constraint removes π0\pi^0, its gauge direction removes A0A_0, Gauss law removes the longitudinal momentum, and the spatial gauge quotient removes the longitudinal potential. The reduced data are therefore

(AiT,πTi),iAiT=iπTi=0.(A_i^T,\pi_T^i), \qquad \partial_iA_i^T =\partial_i\pi_T^i =0.

The local dimension count says the same thing:

8Aμ,πμ2×2first-class constraints=4\underbrace{8}_{A_\mu,\pi^\mu} -2\times \underbrace{2}_{\text{first-class constraints}} =4

phase-space dimensions remain, hence two canonical pairs and two configuration-space polarizations. This count assumes independent, constant-rank constraints and a regular gauge quotient; it is not a theorem about boundary, topological, or zero-mode sectors.

The reduced Hamiltonian is

Hred=12Σd3x(πT2+B[AT]2).H_{\mathrm{red}} =\frac12\int_\Sigma\mathrm d^3x\, \left( \boldsymbol\pi_T^2 +\mathbf B[A^T]^2 \right).

It is positive and contains no A0A_0 or longitudinal data. For nonzero spatial momentum, the induced classical bracket is the transverse projector

{AiT(x),πTj(y)}=Pijδ(3)(xy),Pij=δijij2.\begin{aligned} \{A_i^T(\mathbf x),\pi_T^j(\mathbf y)\} &=\mathsf P_i{}^j \delta^{(3)}(\mathbf x-\mathbf y), \\ \mathsf P_i{}^j &=\delta_i{}^j -\frac{\partial_i\partial^j}{\nabla^2}. \end{aligned}

The inverse Laplacian makes the boundary and zero-mode assumptions visible rather than optional. Zinn-Justin 2021, § 21.5.1, p. 516 gives the transverse projector and the d2d-2 component count. Srednicki 2006, § 55, printed pp. 336–337, author manuscript gives the vanishing-at-infinity assumption, transverse canonical momentum, two polarizations, and reduced Hamiltonian in Coulomb gauge.

The Maxwell Hamiltonian realizes the complete elementary constraint chain:

  • the singular Legendre map yields the primary relation π00\pi^0\approx0;
  • stabilization yields the secondary Gauss constraint iπi0\partial_i\pi^i\approx0;
  • the closed bracket algebra makes both constraints first class;
  • one linked primary–secondary chain corresponds to AμAμ+μαA_\mu\mapsto A_\mu+\partial_\mu\alpha; and
  • restriction followed by the admitted gauge quotient leaves the transverse canonical pair and two physical polarizations.

The order matters. A primary constraint is not yet a gauge choice, a secondary constraint need not be second class, and restriction to the final constraint surface is not yet the gauge quotient.

The next canonical step is Physical-Mode Quantization of the Free Electromagnetic Field, which quantizes the transverse data rather than repeating their classical reduction. General gauge orbits, stabilizers, boundary charges, and the construction of generators belong to Gauge Orbits, Gauss Constraints, and Stabilizers; gauge fixing, ghosts, and cohomological machinery belong to Gauge Fixing, BRST, and BV.

Calling π0=0\pi^0=0 a gauge condition. It is a primary constraint produced by the Legendre map. A gauge condition is an additional representative choice and is not imposed in this derivation.

Inferring first class from a singular Hessian. Singularity only starts the analysis. The Proca field has the same missing A˙0\dot A_0 but a second-class constraint pair; Maxwell’s first-class result follows only after stabilization and bracket classification.

Using Gauss smearing as the whole spacetime transformation. αG-\int\alpha\mathcal G gives δAi=iα\delta A_i=\partial_i\alpha on a slice but leaves A0A_0 unchanged. The Maxwell transformation of all four potential components links this flow to the primary direction with descriptor α˙\dot\alpha.

Dropping surface terms before specifying the phase space. If α\alpha or the canonical data have nontrivial boundary behavior, the generator may require a surface improvement and may carry a charge. Such a direction is not automatically redundancy; the boundary-sensitive interpretation belongs to Gauge Orbits, Gauss Constraints, and Stabilizers.

Applying the transverse count to zero or global modes. The inverse Laplacian and Helmholtz decomposition depend on boundary, falloff, and topology. Harmonic modes and nontrivial global sectors require a separate analysis.

  1. Starting from LM\mathcal L_{\mathrm M}, derive Hc\mathcal H_c before and after spatial integration by parts, including the surface term.

    Solution

    Since πi=F0i\pi^i=F_{0i}, one has A˙i=πi+iA0\dot A_i=\pi_i+\partial_iA_0. Therefore

    Hc=πiA˙iLM=12π2+14FijFij+πiiA0.\begin{aligned} \mathcal H_c &=\pi^i\dot A_i-\mathcal L_{\mathrm M} \\ &=\frac12\boldsymbol\pi^2 +\frac14F_{ij}F_{ij} +\pi^i\partial_iA_0. \end{aligned}

    Integrating the last term by parts gives ΣA0iπi-\int_\Sigma A_0\partial_i\pi^i plus ΣdSA0niπi\int_{\partial\Sigma}\mathrm dS\,A_0n_i\pi^i. Only the declared falloff makes the latter vanish.

  2. Verify the two smeared constraint flows and explain why neither one alone is the full time-dependent Maxwell transformation.

    Solution

    For the displayed P[β]P[\beta], the canonical bracket gives δA0=β\delta A_0=\beta and δAi=0\delta A_i=0. For the displayed Gsp[α]G_{\mathrm{sp}}[\alpha], integration by parts gives δAi=iα\delta A_i=\partial_i\alpha and δA0=0\delta A_0=0. Both leave πμ\pi^\mu unchanged. Neither flow alone changes all four components as a time-dependent Maxwell transformation does; matching δAμ=μα\delta A_\mu=\partial_\mu\alpha ties them by β=α˙\beta=\dot\alpha, after which

    δFμν=μνανμα=0.\delta F_{\mu\nu} =\partial_\mu\partial_\nu\alpha -\partial_\nu\partial_\mu\alpha =0.
  3. For a nonzero Fourier mode with wavevector k\mathbf k, reproduce the physical dimension count directly.

    Solution

    Decompose each spatial vector into two directions orthogonal to k\mathbf k and one parallel direction. Gauss law kiπi=0k_i\pi^i=0 removes the longitudinal momentum, while δAi=ikiα\delta A_i=ik_i\alpha identifies the longitudinal potential. The primary constraint removes π0\pi^0, and the α˙\dot\alpha part of the gauge transformation identifies A0A_0. Two transverse components of AiA_i and their two conjugate momenta remain: four phase-space dimensions, or two polarizations.

  • Brown, J. David. “Singular Lagrangians, Constrained Hamiltonian Systems and Gauge Invariance: An Example of the Dirac–Bergmann Algorithm.” Universe 8, no. 3 (2022): 171. DOI.
  • Srednicki, Mark. Quantum Field Theory. Author-hosted manuscript. Santa Barbara: University of California, 2006. Author’s page.
  • Weinberg, Steven. The Quantum Theory of Fields. Volume I: Foundations. Cambridge: Cambridge University Press, 1995. DOI.
  • Zinn-Justin, Jean. Quantum Field Theory and Critical Phenomena. 5th ed. Oxford: Oxford University Press, 2021. DOI.