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Relativistic Scattering Kinematics

For a two-body reaction, on-shell masses and four-momentum conservation leave two independent Lorentz invariants. The Mandelstam variables s,t,us,t,u package the center-of-mass energy, momentum transfer, and crossed channels; the Källén function determines thresholds and momentum magnitudes; and a bounded interval of tt is exactly the physical scattering-angle range.

Required background. S-Matrix and T-Matrix Normalization fixes which overall delta function has been removed from the invariant amplitude.

Helpful background. Lorentz Field Representations and Poincaré Particle Representations supplies the orbit and invariant-product language used here.

Consider

p1+p2p3+p4,p_1+p_2\longrightarrow p_3+p_4,

with every displayed pip_i future-directed and on shell, pi2=mi2p_i^2=m_i^2. Define

s=(p1+p2)2=(p3+p4)2,t=(p1p3)2=(p2p4)2,u=(p1p4)2=(p2p3)2.\begin{aligned} s&=(p_1+p_2)^2=(p_3+p_4)^2,\\ t&=(p_1-p_3)^2=(p_2-p_4)^2,\\ u&=(p_1-p_4)^2=(p_2-p_3)^2. \end{aligned}

Expanding and using momentum conservation gives

s+t+u=m12+m22+m32+m42.\boxed{s+t+u=m_1^2+m_2^2+m_3^2+m_4^2.}

Only two of the three variables are independent. In the physical ss-channel, s\sqrt{s} is the total center-of-mass energy; tt is the squared transfer from particle 1 to particle 3. These definitions and the sum rule agree with the convention-explicit treatment in Schwartz 2014, § 7.4.1, pp. 98–99.

Define

λ(x,y,z)=x2+y2+z22xy2xz2yz=[x(y+z)2][x(yz)2].\lambda(x,y,z) =x^2+y^2+z^2-2xy-2xz-2yz =\big[x-(\sqrt y+\sqrt z)^2\big] \big[x-(\sqrt y-\sqrt z)^2\big].

In the center-of-mass frame, P=p1+p2=(s,0)P=p_1+p_2=(\sqrt{s},\mathbf0). Solving Pp1=(s+m12m22)/2P\cdot p_1=(s+m_1^2-m_2^2)/2 yields

E1=s+m12m222s,E2=s+m22m122s,pi=λ(s,m12,m22)2s.\begin{aligned} E_1&=\frac{s+m_1^2-m_2^2}{2\sqrt{s}}, &E_2&=\frac{s+m_2^2-m_1^2}{2\sqrt{s}},\\ |\mathbf p_i|&=\frac{\sqrt{\lambda(s,m_1^2,m_2^2)}}{2\sqrt{s}}. \end{aligned}

Similarly,

E3=s+m32m422s,E4=s+m42m322s,pf=λ(s,m32,m42)2s.\begin{aligned} E_3&=\frac{s+m_3^2-m_4^2}{2\sqrt{s}}, &E_4&=\frac{s+m_4^2-m_3^2}{2\sqrt{s}},\\ |\mathbf p_f|&=\frac{\sqrt{\lambda(s,m_3^2,m_4^2)}}{2\sqrt{s}}. \end{aligned}

A physical reaction therefore requires

s(m1+m2)2,s(m3+m4)2.s\ge (m_1+m_2)^2, \qquad s\ge (m_3+m_4)^2.

The other zero, s=(mamb)2s=(m_a-m_b)^2, is a pseudothreshold of the algebraic square root; it is not the production threshold for two future-directed particles of masses ma,mbm_a,m_b. At the final-state threshold, pf0|\mathbf p_f|\to0.

These center-of-momentum energies, square roots, and physical threshold branches are worked through with the same covariant normalization in Srednicki 2007, § 11, pp. 93–101.

The scattering angle is an invariant interval

Section titled “The scattering angle is an invariant interval”

Choose the center-of-mass zz axis along p1\mathbf p_1 and let θ\theta be the angle between p1\mathbf p_1 and p3\mathbf p_3. Then

t=m12+m322E1E3+2pipfcosθ.t=m_1^2+m_3^2-2E_1E_3 +2|\mathbf p_i||\mathbf p_f|\cos\theta.

Substituting the invariant energies gives

t=m12+m32(s+m12m22)(s+m32m42)2s+λ(s,m12,m22)λ(s,m32,m42)2scosθ.\begin{aligned} t={}&m_1^2+m_3^2 -\frac{(s+m_1^2-m_2^2)(s+m_3^2-m_4^2)}{2s}\\ &+\frac{\sqrt{\lambda(s,m_1^2,m_2^2)} \sqrt{\lambda(s,m_3^2,m_4^2)}}{2s}\cos\theta. \end{aligned}

Thus the physical interval is ttt+t_-\le t\le t_+, where tt_- is obtained at cosθ=1\cos\theta=-1 and t+t_+ at cosθ=+1\cos\theta=+1. The Jacobian is

dtdcosθ=2pipf=λiλf2s.\frac{\mathrm dt}{\mathrm d\cos\theta} =2|\mathbf p_i||\mathbf p_f| =\frac{\sqrt{\lambda_i\lambda_f}}{2s}.

Equivalently, proposed invariants (s,t)(s,t) describe a real two-body collision only if both Källén functions are nonnegative and

2s(tm12m32)+(s+m12m22)(s+m32m42)λ(s,m12,m22)λ(s,m32,m42)1.\left| \frac{2s(t-m_1^2-m_3^2) +(s+m_1^2-m_2^2)(s+m_3^2-m_4^2)} {\sqrt{\lambda(s,m_1^2,m_2^2)} \sqrt{\lambda(s,m_3^2,m_4^2)}} \right|\le1.

The quantity inside the absolute value is cosθ\cos\theta. This invariant inequality is often a cleaner physical-region check than constructing explicit four-vectors.

For equal masses mi=mm_i=m, elastic scattering has

t=2p2(1cosθ),u=2p2(1+cosθ),t=-2|\mathbf p|^2(1-\cos\theta), \qquad u=-2|\mathbf p|^2(1+\cos\theta),

so the physical ss-channel obeys s4m2s\ge4m^2 and t,u0t,u\le0.

An independent invariant treatment of two-body collision and decay kinematics appears in Weinberg 1995, § 3.4, pp. 134–141.

The figure locates this region and its two crossed counterparts. Inspect the threshold lines and note that the small exchange graphs label which invariant can flow through a propagator; they do not by themselves prove analytic crossing.

For equal masses, the physical s-, t-, and u-channel wedges occupy distinct regions of the Mandelstam plane and correspond to different momentum routings through an exchange graph.

Equal-mass 222\to2 kinematics with s+t+u=4m2s+t+u=4m^2. The ss-channel has s4m2s\ge4m^2 and t,u0t,u\le0; the tt- and uu-channel regions follow by permutation. Threshold locations are exact, the displayed wedges are cropped, and the contact and exchange sketches are schematic and not to scale. Dashed arrows denote crossed continuation as a kinematic relation, not a proof of an analytic crossing theorem.

The same information has a nonvisual form:

Physical interpretation for equal massesTimelike channel invariantOther two invariants
1+23+41+2\to3+4s4m2s\ge4m^2t0t\le0, u0u\le0
1+3ˉ2ˉ+41+\bar3\to\bar2+4t4m2t\ge4m^2s0s\le0, u0u\le0
1+4ˉ3+2ˉ1+\bar4\to3+\bar2u4m2u\ge4m^2s0s\le0, t0t\le0

For 2n2\to n, useful invariants include subsystem masses

sI=(iIpi)2.s_I=\left(\sum_{i\in I}p_i\right)^2.

They are constrained by on-shell conditions, total momentum conservation, and Gram determinants. For any selected vectors v1,,vrv_1,\ldots,v_r, define

Gij=vivj.G_{ij}=v_i\cdot v_j.

In four spacetime dimensions, any five four-vectors are linearly dependent, so detG=0\det G=0 for their 5×55\times5 Gram matrix. The condition is necessary, not sufficient: the on-shell equations, energy signs, and physical-region inequalities must also hold. A list of pairwise invariants that violates any of these constraints describes no real momentum configuration.

For a three-body decay Pp1+p2+p3P\to p_1+p_2+p_3, two pair masses such as s12s_{12} and s23s_{23} provide coordinates on a Dalitz plot. Its boundary occurs when the remaining decay angle reaches cosθ=±1\cos\theta=\pm1, equivalently when the relevant Gram determinant vanishes. Phase space, rather than kinematics alone, supplies the integration measure on that domain.

s,t,us,t,u are always independent.” On-shell four-point kinematics imposes one linear relation. Special masses and dimensions can impose further constraints.

“A zero of λ\lambda is always a physical production threshold.” The factorization has both threshold and pseudothreshold zeros. Future-directed positive-energy kinematics selects the physical branch.

“Crossing is just renaming s,t,us,t,u.” Permuting external momenta maps kinematic formulas, but relating physical amplitudes in separated regions requires analytic continuation, statistics phases, and state conventions.

“Any chosen ss and tt define a real collision.” The Källén functions must be nonnegative and tt must lie in its angular interval. Multi-particle configurations obey additional Gram constraints.

  1. Derive s+t+u=imi2s+t+u=\sum_i m_i^2 by expanding the definitions.

    Answer

    Expand s=m12+m22+2p1p2s= m_1^2+m_2^2+2p_1\cdot p_2, t=m12+m322p1p3t=m_1^2+m_3^2-2p_1\cdot p_3, and u=m12+m422p1p4u=m_1^2+m_4^2-2p_1\cdot p_4. Momentum conservation gives p2p3p4=p1p_2-p_3-p_4=-p_1, so the dot-product combination equals 2m12-2m_1^2. The remaining masses give the stated sum.

  2. For massless 222\to2 scattering, show that t=s2(1cosθ)t=-\tfrac{s}{2}(1-\cos\theta).

    Answer

    With every mass zero, Ei=Ef=s/2E_i=E_f=\sqrt{s}/2 and pi=pf=s/2|\mathbf p_i|=|\mathbf p_f|=\sqrt{s}/2. Substitution in the angle formula gives t=s/2+(s/2)cosθt=-s/2+(s/2)\cos\theta.

  3. At fixed ss above both thresholds, show that the endpoints t±t_\pm coalesce when either the incoming or outgoing pair reaches threshold.

    Answer

    Their separation is

    t+t=4pipf=λ(s,m12,m22)λ(s,m32,m42)s.t_+-t_-=4|\mathbf p_i||\mathbf p_f| =\frac{\sqrt{\lambda(s,m_1^2,m_2^2)} \sqrt{\lambda(s,m_3^2,m_4^2)}}{s}.

    If either Källén function vanishes, the corresponding center-of-mass momentum is zero and no scattering angle remains to vary, so the allowed tt interval collapses to one point.

Lorentz-Invariant Phase Space turns the allowed momentum domain into an integration measure. Mandelstam Channels and Tree-Level Crossing develops channel permutations and analytic continuation. High-Energy and Regge Limits treats the special large-ss limits.

  • Schwartz, Matthew D. Quantum Field Theory and the Standard Model. Cambridge: Cambridge University Press, 2014. DOI.
  • Srednicki, Mark. Quantum Field Theory. Cambridge: Cambridge University Press, 2007. DOI.
  • Weinberg, Steven. The Quantum Theory of Fields. Volume I: Foundations. Cambridge: Cambridge University Press, 1995. DOI.